A) cannot be compared
B) equal to T
C) less than T
D) more than T
Correct Answer: D
Solution :
The time-period \[(T)\] of a simple pendulum is given by \[T=2\pi \sqrt{\frac{l}{g}}\] \[\Rightarrow \] \[T\propto \frac{1}{\sqrt{g}}\] Let mine be at a depth h below the surface of earth of radius R, then \[g=g\left( 1-\frac{h}{R} \right)\]hence, \[g\] decreases. Therefore, \[T\] increases.
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