A) \[\Delta W=0\]
B) \[\Delta U=0\]
C) \[\Delta Q=0\]
D) \[\Delta T=0\]
Correct Answer: A
Solution :
We know that work done by a system \[W=p\times \Delta V\] In an isochoric process change in volume\[\Delta V=0\], therefore, work done. While \[\Delta Q=0\] is in an adiabatic process, \[\Delta U\] or\[\Delta T=0\]in an isothermal process.
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