A) \[3.01\times {{10}^{24}}\]
B) \[4.06\times {{10}^{24}}\]
C) \[2.01\times {{10}^{24}}\]
D) \[3.02\times {{10}^{24}}\]
Correct Answer: A
Solution :
We know that protons in\[1\,\,mole\,\,CaC{{O}_{3}}\] = atomic number of calcium + atomic number of carbon + 3 (atomic number of oxygen) \[=20+6+3(8)=50\,\,mol\] \[\therefore \]proton in\[10\,\,g\,\,CaC{{O}_{3}}=\frac{10\times 50}{100}\times 6.02\times {{10}^{23}}\] \[=3.01\times {{10}^{24}}\]
You need to login to perform this action.
You will be redirected in
3 sec
