A) 516 m/s
B) 450 m/s
C) 310 m/s
D) 746 m/s
Correct Answer: A
Solution :
We know that \[rms\] speed is directly proportional to square root of temperature \[{{v}_{rms}}\times \sqrt{T}\] Hence, \[\frac{{{v}_{rms(1)}}}{{{r}_{rms(2)}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\] \[\frac{400}{{{v}_{rms(2)}}}=\frac{\sqrt{27+273}}{227+273}\] \[=\sqrt{\frac{300}{500}}\] \[{{v}_{rms(2)}}=v=\sqrt{\frac{500}{300}}\times 400\] \[=1.29\times 400\] \[=516.39\,\,m/s\] \[\approx 516\,\,m/s\]
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