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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2006

  • question_answer
    A particle is executing two different simple harmonic motions, mutually perpendicular, of different amplitudes and having phase difference of \[\pi /2.\] The path of the particle will be:

    A)  circular                                

    B)         straight line

    C)         parabolic                            

    D)         elliptical

    Correct Answer: D

    Solution :

    As the different amplitudes are mutually perpendicular which have phase difference of\[\frac{\pi }{2}\]therefore, particle will follow elliptical path.


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