A) \[30{}^\circ \]
B) \[76{}^\circ \]
C) \[50{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: B
Solution :
or projectiles \[{{H}_{\max }}=\frac{{{u}^{2}}{{\sin }^{2}}\alpha }{2\,\,g}\] \[R=\frac{{{u}^{2}}\sin 2\alpha }{g}\] Given\[{{H}_{\max }}=R\] \[\Rightarrow \] \[\frac{{{u}^{2}}{{\sin }^{2}}\alpha }{2\,\,g}=\frac{{{u}^{2}}\sin 2\,\,\alpha }{g}\] \[\Rightarrow \] \[{{\sin }^{2}}\alpha =4\sin \alpha \cos \alpha \] \[\Rightarrow \] \[\tan \alpha =4\Rightarrow \alpha ={{\tan }^{-1}}4\] \[\Rightarrow \] \[\alpha ={{76}^{o}}\]
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