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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2006

  • question_answer
    Distance between successive compression and rarefaction is 1 m and velocity of sound is 360 ms-1. Find frequency :

    A)  180 Hz                                 

    B)         45 Hz

    C)         120 Hz                                 

    D)         90 Hz

    Correct Answer: A

    Solution :

    \[\lambda =2\,\,d=2\,\,m\]                 \[v=\frac{v}{\lambda }=\frac{360\,\,m{{s}^{-1}}}{2\,\,m}=180\,\,Hz\] Reason: As it can be understood from the figure, distance between successive compressions and rarefactions is one half of the wavelength.


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