RAJASTHAN PMT Rajasthan - PMT Solved Paper-2006

  • question_answer
    If separation between screen and source is in cresed by 2%, what would be the effect on the intensity?

    A)  Increases by 4%              

    B)  Increases by 2%

    C)  Decreases by 2%            

    D)  Decreases by 4%

    Correct Answer: D

    Solution :

    Intensity\[\propto \frac{1}{{{r}^{2}}}\] \[\Rightarrow \]               \[\frac{{{I}_{2}}}{{{I}_{1}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}={{\left( \frac{{{r}_{1}}}{{{r}_{1}}(1+2%)} \right)}^{2}}\] \[\Rightarrow \]               \[{{I}_{2}}={{I}_{1}}{{(1+2%)}^{-2}}\] Expanding by binomial theorem \[\Rightarrow \]               \[{{I}_{2}}={{I}_{1}}(1-4%)\] \[\therefore \]Intensity decreases by\[4%\].


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