RAJASTHAN PMT Rajasthan - PMT Solved Paper-2006

  • question_answer
    Amplitude of a pendulum is 60 mm and angular velocity is 2 rad s-1. Find its velocity if its displacement is 22 mm:

    A)  \[120\,\,mm\,{{s}^{-1}}\]                           

    B)  \[113\,\,mm\,{{s}^{-1}}\]

    C)  \[115\,\,mm\,{{s}^{-1}}\]           

    D)         \[125\,\,mm\,{{s}^{-1}}\]

    Correct Answer: B

    Solution :

    \[\omega =2\,\,rad/{{s}^{-1}},\,\,y=20\,\,mm,\,\,a=60\,\,mm\] \[v=\omega \sqrt{{{a}^{2}}-{{y}^{2}}}\]                 \[=\sqrt{{{(60)}^{2}}-{{(20)}^{2}}}\]                 \[=113\,\,mm/{{s}^{-1}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner