A) it occupies \[2.24\,\,litre\] at\[NTP\]
B) it corresponds to \[\frac{1}{2}\] mole of\[CO\]
C) it corresponds to same mole of \[CO\] and \[{{N}_{3}}\]
D) it corresponds to\[3.01\times {{10}^{23}}\]molecules of \[CO\]
Correct Answer: A
Solution :
\[14\,\,g\] of\[CO=\frac{14}{28}=0.5\]mole \[0.5\,\,mole=3.01\times {{10}^{23}}\]molecules The molecular weight of \[CO=(12+16)=28\] The molecular weight of \[{{N}_{2}}=14+14=28\] Therefore, the incorrect statement as that it occupies \[2.24\,\,litre\] at\[NTP\].
You need to login to perform this action.
You will be redirected in
3 sec
