A) \[[M{{L}^{-1}}{{T}^{-2}}]\]
B) \[[ML{{T}^{-2}}]\]
C) \[[M{{L}^{-1}}{{T}^{-1}}]\]
D) \[[{{M}^{-1}}{{L}^{2}}{{T}^{-2}}]\]
Correct Answer: C
Solution :
\[F=-\eta A\frac{d\upsilon }{dc}\] \[\therefore \] \[\eta =-\frac{F}{A}\frac{dx}{d\upsilon }\] Writing the dimensions \[[\eta ]=\frac{[ML{{T}^{-2}}]}{[{{L}^{2}}]}\frac{[L]}{[L{{T}^{-1}}]}\] \[=[M{{L}^{-1}}{{T}^{-1}}]\]You need to login to perform this action.
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