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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2005

  • question_answer
    If the pressure of a gas contained in a vessel is increased by 0.4% when heated through 1\[{}^\circ C\], the initial temperature had been:

    A)  2500 K                 

    B)         250 K

    C) \[250{}^\circ C\]              

    D)        \[25{}^\circ C\]

    Correct Answer: C

    Solution :

    According to Charles law \[\frac{dp}{p}=\frac{dT}{T}\] Here:       \[dT=1{}^\circ C\] dP is change in pressure = 0.4%                                 \[\frac{dp}{p}=\frac{0.4}{100}\] or            \[\frac{0.4}{100}=\frac{1}{T}\] So,          \[T=\frac{100}{0.4}=250{}^\circ C\]


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