RAJASTHAN PMT Rajasthan - PMT Solved Paper-2005

  • question_answer
    The wavelength associated with an electron accelerated through a potential difference of 100 V is of the order of:

    A)  \[1.2\,\overset{\text{o}}{\mathop{\text{A}}}\,\]                           

    B)  \[10.5\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C)  \[100\,\overset{\text{o}}{\mathop{\text{A}}}\,\]          

    D)         \[1000\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: A

    Solution :

    Here: Potential difference V = 100 V We know that de-Broglie wavelength of an electron is given by \[\lambda =\frac{h}{\sqrt{2qVm}}\] \[=\frac{6.6\times {{10}^{-34}}}{2\times (1.6\times {{10}^{-19}})\times 100\times 9.1\times {{10}^{-31}}}\] \[=1.2\times {{10}^{-10}}m\] \[=1.2\overset{{}^\circ }{\mathop{\text{A}}}\,\]


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