RAJASTHAN PMT Rajasthan - PMT Solved Paper-2004

  • question_answer
    When amonia is heated with dry alkali metal in presence of \[Fe,\] the product obtained is:

    A)  \[Fe,\] complex, \[{{H}_{2}}\]

    B)  metal amide, \[{{H}_{2}}\]

    C)  alkaline complex, \[{{H}_{2}}\]

    D)  alkaline complex

    Correct Answer: B

    Solution :

    Dry ammonia, when passed over sodium heated at about \[{{400}^{o}}C,\]it forms, sodamide. \[2Na+2N{{H}_{3}}\xrightarrow{{}}\underset{sodamide}{\mathop{2NaN{{H}_{2}}}}\,+{{H}_{2}}\]


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