RAJASTHAN PMT Rajasthan - PMT Solved Paper-2004

  • question_answer
    pH of \[N/100\text{ }\] \[HCl\]will be:

    A)  \[1\]                                    

    B)  \[4\]

    C)  \[0.2\]                 

    D)         \[2\]

    Correct Answer: D

    Solution :

    \[pH=-\log [{{H}^{+}}]\] \[=-\log \frac{1}{100}\] \[=2\]


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