A) \[Conc.HCl+ZnC{{l}_{2}}\]
B) \[N{{H}_{2}}\text{ }N{{H}_{2}}/{{C}_{2}}{{H}_{5}}ONa\]
C) \[Zn-Hg/HCl\]
D) None of the above
Correct Answer: A
Solution :
The mixture of \[ZnC{{l}_{2}}\]and cone. \[HCl\] is called Lucas reagent. It is used in distinguishing \[{{1}^{o}},\] \[{{2}^{o}}\] and \[{{3}^{o}}\] alcohol. Tertiary alcohols give white turbidity with this immediately, while secondary alcohol give turbidity after 5 minutes. Whereas \[{{1}^{o}}\] alcohol do not react at all.
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