A) \[C{{u}_{2}}{{C}_{2}}\]
B) \[CuCHCl\]
C) \[~C{{H}_{4}}\]
D) none of these
Correct Answer: A
Solution :
Acetylene reacts with ammonical cuprous chloride to form the precipitate of cuprous acetylide. \[CH\equiv CH+C{{u}_{2}}C{{l}_{2}}+2N{{H}_{4}}OH\xrightarrow{{}}\underset{White\,ppt.}{\mathop{\underset{C.\,\,Cu}{\overset{C.\,\,Cu}{\mathop{||\,\,|}}}\,}}\,\] \[+2N{{H}_{4}}Cl+2{{H}_{2}}O\]
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