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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2004

  • question_answer
    On increasing the temperature of a gas contained in a closed vessel by \[1{}^\circ C\], the pressure increases by 0.4%. The initial temperature of gas is:

    A)  25 K                                      

    B)  250 K

    C)  \[2500{}^\circ C\]           

    D)         \[250{}^\circ C\]

    Correct Answer: B

    Solution :

    Law of pressure is \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] \[\Rightarrow \]               \[\frac{P}{P+\frac{P\times 0.4}{100}}=\frac{x+273}{x+(273+1}\] \[\Rightarrow \]               \[\frac{250}{251}=\frac{x+273}{x+274}\] \[\therefore \]  \[x=23{}^\circ C=250K\]


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