A) two fold
B) half
C) four fold
D) one fourth
Correct Answer: D
Solution :
The force between two charges\[q\]and\[-q\] is \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q\times -q}{{{r}^{2}}}=-\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}^{2}}}{{{r}^{2}}}\] where r = separation between the charges \[\therefore \] \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q\times -q}{r{{}^{2}}}\] \[=-\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{q}{{{(2r)}^{2}}}\,\,(\therefore r=2r)\] \[=\frac{1}{4}F\]
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