A) 16 times
B) 8 times
C) \[2\sqrt{2}\] times
D) 32 times
Correct Answer: A
Solution :
From Stefans law \[E\propto {{T}^{4}}\] \[\therefore \,\,\,\,\,\,\frac{{{E}_{1}}}{{{E}_{2}}}\,={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}\] Here \[{{E}_{1}}=E\] (initial radiation say), \[{{T}_{1}}=T,{{T}_{2}}=2T\] Putting given values in eq (1) \[\Rightarrow \] \[{{E}_{2}}=16E\]
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