A) 3.4 eV
B) 10.2 eV
C) 13.6 eV
D) 1.51 eV
Correct Answer: B
Solution :
The energy of electron in \[{{n}^{th}}\] bohr orbit \[E=-\frac{13.6}{{{n}^{2}}}\] Energy absorbed by electron in transition from \[n=1\to n=2\] \[\therefore \] \[E-=\frac{13.6}{{{2}^{2}}-\left( \frac{13.6}{{{1}^{2}}} \right)}\] \[=-\frac{13.6}{4}+\frac{13.6}{1}\] \[\begin{align} & =-3.4+13.6 \\ & =10.2\,eV \\ \end{align}\]
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