A) \[{{10}^{-3}}\,mm\] mm of Hg
B) \[{{10}^{-7}}\,mm\] of Hg
C) 10 mm of Hg
D) \[{{10}^{-4}}\,mm\] of Hg
Correct Answer: A
Solution :
The pressure maintained in a Coolidge tube is equal to \[{{10}^{-3}}\,mm\] of Hg.
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