RAJASTHAN PMT Rajasthan - PMT Solved Paper-2004

  • question_answer
    In nuclear fission, 0.1% mass is converted into energy. The energy released by the fission of 1 kg mass is:

    A)  \[2.5\times {{10}^{7}}\,kWh\]

    B)  \[2.5\,\times {{10}^{3}}kWh\]

    C)  \[2.5\,\times {{10}^{6}}kWh\]  

    D)         \[2\times {{10}^{8}}kWh\]

    Correct Answer: A

    Solution :

    \[\Delta E=m{{c}^{2}}\] \[\Delta E=\frac{0.1}{100}\times 9\times {{10}^{16}}J\] \[=\frac{9\times {{10}^{13}}}{36\times {{10}^{5}}}kWh\] \[=2.5\times {{10}^{7}}kWh\]


You need to login to perform this action.
You will be redirected in 3 sec spinner