RAJASTHAN PMT Rajasthan - PMT Solved Paper-2004

  • question_answer
    The distance between the ends of wings of an aeroplane is 5 m. The aeroplane is moving with velocity of 200 km/sec in a magnetic field of 10 T. The emf induced across the ends of wings will be:

    A)  \[{{10}^{7}}\] volt          

    B)         10 volt

    C)  \[{{10}^{6}}\] volt          

    D)         none of these

    Correct Answer: A

    Solution :

                               \[e=B\upsilon l\]                                   ?(i) Here: \[B=10\,T,\upsilon =200km/\sec \]                                            \[=2\times {{10}^{5}}\,m/\sec ,\,l=5m\] Putting given values is eq (i) \[\therefore \,\,\,\,\,\,\,\,\,\,e=10\,\times 2\times {{10}^{5}}\,\times 5\]                 \[=1\times {{10}^{7}}\,volt\]


You need to login to perform this action.
You will be redirected in 3 sec spinner