A) 1.2 V
B) 2 V
C) 0.8 V
D) 1 V
Correct Answer: C
Solution :
The equivalent resistance of the circuit \[R=\left( \frac{4\times 2}{4+2} \right)+2=\frac{8}{6}+2=\frac{20}{6}\] \[=\frac{10}{3}\Omega \] \[\therefore \]Current through the circuit \[i=\frac{V}{R}=\frac{2}{10/3}=\frac{6}{10}=\frac{3}{5}A\] Therefore, potential difference across BC \[V=\frac{3}{5}\left( \frac{4\times 2}{4+2} \right)=0.8\,volt\]
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