A) 1-Butene
B) Ethylene
C) Ethane
D) 2-Butene
Correct Answer: D
Solution :
Ethylidene dibromide on heating with metallic sodium produce 2-Butene. \[\underset{\text{Ethylidene dibromide}}{\mathop{C{{H}_{3}}-\underset{Br}{\mathop{\underset{|}{\mathop{\overset{Br}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-H+4Na}}\,+H-\underset{Br}{\mathop{\underset{|}{\mathop{\overset{Br}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{3}}\xrightarrow[\Delta ]{ether}\] \[\underset{2-Butene}{\mathop{C{{H}_{3}}-CH=CH}}\,-C{{H}_{3}}+4NaBr\]
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