A) \[Al+C{{l}_{2}}~\]
B) \[Al+dil.\text{ }HCl\]
C) \[Al+con;\text{ }HCl\]
D) \[Al+dry\text{ }HCl\text{ }gas\]
Correct Answer: D
Solution :
Anhydrous \[AlC{{l}_{3}}\]is prepared by heating aluminium with dry \[HCl\] gas. \[\underset{dry\,HCl\,gas}{\mathop{2Al+6HCl}}\,\xrightarrow{{}}2AlC{{l}_{3}}+3{{H}_{2}}\]
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