A) \[C{{H}_{3}}COOH\]is formed
B) \[C{{H}_{3}}CHO\]is formed
C) \[C{{H}_{3}}C{{H}_{2}}OH\]is formed
D) None of these
Correct Answer: B
Solution :
\[\underset{Acetylchloride}{\mathop{C{{H}_{3}}COCl}}\,\xrightarrow[\text{Reduction}]{BaS{{O}_{4}}+Pd}\underset{Acetaldehyde}{\mathop{C{{H}_{3}}CHO}}\,\]
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