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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2003

  • question_answer
    A tube closed at one end produces a note B of frequency 512 Hz. If the tube is opened k at both ends, the frequency will become

    A)  512 Hz                 

    B)         256 Hz

    C)  128 Hz                 

    D)         1024 Hz

    Correct Answer: D

    Solution :

    For a closed pipe, fundamental frequency, \[n=\frac{v}{4l}=512Hz\] For an open pipe, fundamental frequency, \[n=\frac{v}{2l}=2\times \left( \frac{v}{4l} \right)\]        \[=2\times 512\,Hz=1024\,Hz\]


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