A) \[\mu \]
B) \[\frac{\mu }{2}\]
C) \[\frac{\mu }{4}\]
D) \[2\mu \]
Correct Answer: B
Solution :
Voltage gain in a triode \[{{A}_{v}}=\frac{\mu {{R}_{L}}}{{{R}_{p}}+{{R}_{L}}}\] Here \[{{R}_{p}}={{R}_{L}}\] \[\therefore \] \[{{A}_{v}}=\frac{\mu \times {{R}_{L}}}{{{R}_{L}}+{{R}_{L}}}\] \[=\frac{\mu {{R}_{L}}}{2{{R}_{L}}}=\frac{\mu }{2}\]
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