A) \[0.6\,{{m}_{0}}\]
B) \[0.8\,{{m}_{0}}\]
C) \[\frac{5}{3}\,{{m}_{0}}\]
D) \[1.25\,{{m}_{0}}\]
Correct Answer: C
Solution :
According to theory of relativity, \[m=\frac{{{m}_{0}}}{\sqrt{1\left( -\frac{{{\upsilon }^{2}}}{{{c}^{2}}} \right)}}\] Here \[u\] = 0.8 c \[\therefore \] \[^{m=}\frac{{{m}_{0}}}{\sqrt{\left\{ 1-{{\frac{0.8\,c}{c}}^{2}} \right\}}}\] \[=\frac{{{m}_{0}}}{\sqrt{1-0.64}}=\frac{{{m}_{0}}}{0.6}\] \[=\frac{5}{3}{{m}_{0}}\]
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