A) \[[M{{L}^{3}}{{T}^{-2}}]\]
B) \[[M{{L}^{5}}{{T}^{-2}}]\]
C) \[[M{{L}^{2}}{{T}^{-1}}]\]
D) \[[M{{L}^{2}}{{T}^{-5}}]\]
Correct Answer: B
Solution :
Pressure P and \[\frac{a}{{{V}^{2}}}\](V=volume) must have same dimensions \[\therefore \]dimensions of [P] = dimensions of \[\left[ \frac{a}{{{V}^{2}}} \right]\] \[\Rightarrow \]dimensions of\[[a]\] = dimensions of \[[P{{V}^{2}}]\] \[=[M{{L}^{-1}}{{T}^{-2}}]\times {{({{L}^{3}})}^{2}}]\] \[=[M{{L}^{5}}{{T}^{-2}}]\]
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