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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2003

  • question_answer
    An \[\text{-}\]particle is bombarded on \[{{N}^{14}}\]. As a result a \[{{O}^{17}}\]-nucleus is formed and a particle X is emitted. The particle X is

    A)  neutron                             

    B)  proton

    C)  electron             

    D)         positron

    Correct Answer: B

    Solution :

    According to question reaction may be expressed as \[_{2}H{{e}^{4}}{{+}_{7}}{{N}^{14}}{{\xrightarrow{{}}}_{8}}{{O}^{17}}+{{ & }_{1}}{{X}^{1}}\] (proton) So, particle X is a proton (1H1)


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