A) \[N{{H}_{4}}^{\oplus }\]
B) \[N{{H}_{2}}^{\oplus }\]
C) \[N{{H}_{2}}^{\bigcirc -}\]
D) \[{{N}_{2}}\]
Correct Answer: C
Solution :
Conjugate base of \[N{{H}_{3}}\]is \[NH_{2}^{-}\]. \[AcidBase+{{H}^{+}}\] \[N{{H}_{3}}\xrightarrow{{}}NH_{2}^{-}+{{H}^{+}}\]
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