RAJASTHAN PMT Rajasthan - PMT Solved Paper-2002

  • question_answer
    In a showing figure find the equivalent resistance between A and B.

    A)  2/3 ohm             

    B)         5/ ohm

    C)  8/9 ohm             

    D)         7.5 ohm

    Correct Answer: D

    Solution :

    The figure can be shown as equivalent resistance of \[{{R}_{1}},\]\[{{R}_{2}}\]and\[{{R}_{3}}\]                                 \[R={{R}_{1}}+{{R}_{2}}+{{R}_{3}}\]                                 \[=5+5+5=15\,\Omega \] Equivalent resistance of\[{{R}_{4}}{{R}_{5}}\]  and \[{{R}_{6}}\] \[\begin{align}   & R=5+5+5=15\Omega  \\  & {{R}_{AB}}=\frac{RR}{R+R} \\ \end{align}\] \[=\frac{15\times 15}{15+15}=\frac{15}{2}=7.5\,\text{ohm}\]


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