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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2002

  • question_answer
    Amplification factor of triode is 18 and internal resistance is 8000\[\Omega \] If load resistance is 10, 000 \[\Omega ,\]then the voltage amplification of triode is:

    A)  20                         

    B)         10   

    C)  40                         

    D)         15

    Correct Answer: B

    Solution :

    \[\mu =18,{{R}_{P}}=8000\,\Omega ,\]\[{{R}_{L}}=10,000\,\Omega \] Voltage amplification \[A=\frac{\mu {{R}_{L}}}{{{R}_{P}}+{{R}_{L}}}\] \[=\frac{18\times 10,\,000}{8000+10,\,000}\]                                 \[=\frac{18\times 10,000}{18000}=10\]


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