A) \[-123{}^\circ C\]
B) \[240{}^\circ C\]
C) \[27{}^\circ C\]
D) \[0{}^\circ C\]
Correct Answer: A
Solution :
When tyre brusts then pressure becomes equal to the pressure of atmosphere, \[\frac{{{P}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}}{{{T}_{2}}}\] \[\frac{2}{273+27}=\frac{1}{{{T}_{2}}}\] \[{{T}_{2}}=150\,K\] \[=123\,{}^\circ C\]
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