2. Solved Papers
  3. RAJASTHAN PMT

RAJASTHAN PMT Rajasthan - PMT Solved Paper-2002

  • question_answer
    A torque of 30 N-m is acting on a wheel of mass 5 kg and moment of inertia 2 kg-m2. If wheel starts rotating from rest then, its angular displacement in 10 seconds will be:

    A)  750 rad   

    B)         1500 rad

    C)  3000 rad             

    D)         6000 rad

    Correct Answer: A

    Solution :

                                          \[t=I\,\alpha \] \[30=2\times \alpha \] \[\Rightarrow \]               \[\alpha =15\,rad/{{\sec }^{2}}\] From equation of angular motion                                 \[\,\text{=}{{\omega }_{0}}t+\frac{1}{2}\alpha {{t}^{2}}\] \[\begin{align}   & \,\text{=}\,\text{0}+\frac{1}{2}\times 15\times 10\times 10 \\  & =750\,\text{rad} \\ \end{align}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner