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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    \[{{N}_{2}}{{O}_{4}}2N{{O}_{2}}\] In this reaction the dissociation of \[{{N}_{2}}{{O}_{4}}\] is X then the how much mole will of \[{{N}_{2}}{{O}_{4}}\] and \[N{{O}_{2}}\] at equilibrium:

    A)  \[{{(1-x)}^{2}}\]                              

    B)  \[1\]

    C)  \[(1+x)\]            

    D)         \[2\]

    Correct Answer: C

    Solution :

    At equilibrium \[\underset{t=t}{\mathop{\underset{t=0}{\mathop{{{N}_{2}}{{O}_{4}}}}\,}}\,\underset{(2-x)=2x}{\mathop{\underset{1}{\mathop{2N{{O}_{2}}}}\,}}\,\] Total number of mole \[=1-x+2x\]                                                                 \[=1+x\]


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