A) \[2.69\]
B) \[8.67\]
C) \[1.69\]
D) \[3.57\]
Correct Answer: B
Solution :
We know that for weak acid. \[pH{{=}_{p}}{{K}_{\omega }}{{-}_{p}}{{K}_{a}}+\log C\] \[\because \] \[_{p}{{K}_{\omega }}=14\] \[_{p}{{K}_{a}}=3.37\] \[C=0.01mole/litre\] \[pH=14-3.37+\log 0.01\] \[pH=14-3.37-2\] \[pH=8.67\]
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