RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    \[Cu\] have the F.C.C. unit cell and length is 362 Pm what will be density of copper:

    A)  \[6.29g/c{{m}^{3}}~\]

    B)  \[2.23\text{ }g/c{{m}^{3}}\]

    C)  \[4.45\text{ }g/c{{m}^{3}}\]    

    D)  \[8.90\text{ }g/c{{m}^{3}}\]

    Correct Answer: B

    Solution :

    Density of copper \[=\frac{Z\times M}{{{a}^{3}}\times {{N}_{0}}\times {{10}^{-30}}}g\,c{{m}^{-3}}\] Here \[a=362Pm,\] \[{{N}_{0}}=6.09\times {{10}^{23}}\] \[Z=12\] in \[FCC,\] \[M=63.546\] \[Density=\frac{12\times 63.546}{{{(362)}^{3}}\times 6.09\times {{10}^{23}}\times {{10}^{-30}}}\]                 \[=2.23g\,c{{m}^{3}}\]


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