A) \[FeC{{l}_{3}}\] and \[SrB{{r}_{2}}\]
B) \[N{{a}_{2}}C{{O}_{3}}\]and \[CaC{{l}_{2}}\]
C) \[{{H}_{2}}S{{O}_{4}}\]and \[N{{H}_{3}}\]
D) \[NaN{{O}_{3}}\]and \[Pb{{(N{{O}_{3}})}_{2}}\]
Correct Answer: B
Solution :
\[N{{a}_{2}}C{{O}_{3}}+CaC{{l}_{2}}\xrightarrow{{}}\underset{PPt}{\mathop{CaC{{O}_{3}}}}\,+2NaCl\]
You need to login to perform this action.
You will be redirected in
3 sec
