A) amplitude and time period
B) amplitude, time period and displacement
C) amplitude and displacement
D) time period and displacement
Correct Answer: A
Solution :
Total energy of particle executing S.H.M. \[\begin{align} & =\frac{1}{2}m{{\omega }^{2}}{{a}^{2}} \\ & =\frac{1}{2}m4{{\pi }^{2}}{{n}^{2}}{{a}^{2}} \\ \end{align}\] \[\therefore \]total energy depends upon amplitude and time period (frequency).
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