RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    Change in acceleration duo to gravity is same upto a height\[h\]from earth surface and below depth \[x\] then relation between \[x\] and \[h\] is \[(h\,\text{and}\,x\,<<<\,\operatorname{Re}):\]

    A)  \[x=h\]                               

    B)         \[x=2h\]

    C)  \[x=\frac{h}{2}\]            

    D)                         \[x={{h}^{2}}\]

    Correct Answer: B

    Solution :

    Variation in g at a height h from earth surface \[g=g\left( 1-\frac{2h}{{{R}_{e}}} \right)\]                                                            ?(1) Variation in g at a depth x below earth surface                               \[g=g\left( 1-\frac{x}{{{R}_{e}}} \right)\]                                                               ?(2) Variations arc same             \[\begin{align}   & \therefore \left( 1-\frac{2h}{{{R}_{e}}} \right)=g\left( 1-\frac{x}{{{R}_{e}}} \right) \\  & \therefore \,x=2h \\ \end{align}\]


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