A) 2-methyl butane and neopentane
B) \[C{{H}_{3}}CHC{{l}_{2}}\]and \[ClC{{H}_{2}}C{{H}_{2}}Cl\]
C) Dethyl ether and propyl ether
D) Propyl alcohol and isopropyl alcohol
Correct Answer: A
Solution :
\[\underset{2-methyl\,\,\text{butane}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{2}}-C{{H}_{3}}}}\,\] \[\underset{\text{Neopentane}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{3}}}}\,\] Both are show chain isomerism.
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