A) schiffs base
B) benzoin
C) azoxy benzene
D) unsaturated acid
Correct Answer: A
Solution :
\[{{C}_{6}}{{H}_{5}}N{{H}_{2}}+O=CH{{C}_{6}}{{H}_{5}}\xrightarrow{{{120}^{o}}C}\] \[\underset{\begin{smallmatrix} Benzilidine\,\,\text{amine} \\ [Schiff\,base] \end{smallmatrix}}{\mathop{{{C}_{6}}{{H}_{5}}N=CH.{{C}_{6}}{{H}_{5}}}}\,+{{H}_{2}}O\]
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