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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    A swing is revolving in vertical plane, its height from ground in lowermost and uppermost position or 1 metre and 5 metre. Then its velocity at uppermost point will be:

    A)  \[\sqrt{2}g\]                     

    B)         \[2\sqrt{g}\]  

    C)  \[2g\]                                  

    D)         \[4g\]

    Correct Answer: A

    Solution :

    Radius of circular orbit = 2 metre Speed at highest point\[\upsilon =\sqrt{gr}\Rightarrow \sqrt{2g}\]


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