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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    A train is stopped by applying breaks, then it stops after covering 50 m. If initial velocity of train is double than before and train is stopped with same force, then the train will stop at a distance of:

    A)  50 metre            

    B)         100 metre

    C)  200 metre         

    D)         400 metre

    Correct Answer: C

    Solution :

    According to 2nd equation of motion \[\begin{align}   & {{\upsilon }^{2}}={{u}^{2}}-2as \\  & 0={{u}^{2}}-2a\times 50 \\ \end{align}\] \[\Rightarrow \]               \[a=\frac{{{u}^{2}}}{100}\] If initial velocity is doubled \[0={{(2u)}^{2}}-2as\] \[s=\frac{4{{u}^{2}}}{2a}=\frac{2{{u}^{2}}\times 100}{{{4}^{2}}}\] \[=200\,\text{meter}\]


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