RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    On giving 220 V to a resistor the power dissipated is 40 watt, then the value of resistance is:                       

    A)  1210\[\Omega \]            

    B)         2000\[\Omega \]      

    C)  1000\[\Omega \]            

    D)         none of these

    Correct Answer: A

    Solution :

    Electric power\[p=\frac{{{V}^{2}}}{{{R}^{2}}}\] \[40=\frac{220\times 220}{R}\] \[R=1210\Omega \]       


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