A) \[17.6\times {{10}^{16}}\]
B) \[14.5\times {{10}^{12}}\]
C) \[1.76\times {{10}^{15}}\]
D) \[1.45\times {{10}^{15}}\]
Correct Answer: C
Solution :
If electron is accelerated by voltage V, then its kinetic energy\[\frac{1}{2}m{{\upsilon }^{2}}=qV\] \[\frac{q}{m}=\frac{{{\upsilon }^{2}}}{2V}=\frac{{{(8.4\times {{10}^{8}})}^{2}}}{2\times 200}\] \[=1.76\times {{10}^{15}}\]
You need to login to perform this action.
You will be redirected in
3 sec
